Free Practice Questions for C++ Institute CPP Exam

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

void myfunction(int i) {

cout << " " << i;

}

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

vector v1(t, t + 10);

deque d1(t, t + 10);

set s1(t, t + 10);

for_each(v1.begin(), v1.end(), myfunction); // Line I

for_each(d1.begin(), d1.end(), myfunction); // Line II

for_each(s1.begin(), s1.end(), myfunction); // Line III

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

};

bool Compare(char a, char b) { return tolower(a) < tolower(b);}

int main() {

char s[]={"qwerty"};

char t1[]={"ert"};

char t2[]={"ERT"};

sort(s, s+6);

cout<

return 0;

}

Program outputs:

What will happen when you attempt to compile and run the code below, assuming that file test.in contains the following sequence: 1 2 3?

#include

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) {out<

int main () {

ifstream f("test.in");

list l;

for( ; f.good() ; ) {

int i;

f>>i;

l.push_back(i);

}

f.close();

for_each(l.begin(), l.end(), Out(cout));

return 0;

}

Program will output:

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t1[]={3,2,4,1,5};

int t2[]={5,6,8,2,1};

vector v1(10);

sort(t1, t1+5);

sort(t2, t2+5);

set_intersection(t1,t1+5,t2,t2+5,v1.begin());

for_each(v1.begin(), v1.end(), Out(cout));cout<

return 0;

}

Program outputs:

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(){

int t[] ={ 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };

listv(t, t+10);

set s1(v.begin(),v.end());

if (s1.count(3) == 2) {

s1.erase(3);

}

for(set::iterator i=s1.begin();i!= s1.end(); i++) {

cout<<*i<<" ";

}

return 0;

}

What happens when you attempt to compile and run the following code?

include

#include

#include

#include

#include

using namespace std;

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

vector v1(t, t + 10);

deque d1(t, t + 10);

set s1(t, t + 10);

cout<

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

int main(){

int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };

vector v(t, t+10);

map m;

for(vector::iterator i=v.begin(); i!=v.end(); i++) {

stringstream s; s<<*i<<*i; m.insert(pair(*i,s.str()));

}

for(map::iterator i=m.begin();i!= m.end(); i++) {

cout<<*i<<" ";

}

return 0;

}

Which method added to class B at the marked spot will allow the code below to compile? Choose all possible solutions.

#include

#include

#include

using namespace std;

class B { int val;

public:

B(int v):val(v){}

int getV() const {return val;}

/* Insert Code Here */

};

ostream & operator <<(ostream & out, const B & v) { out<

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

vector v1(t, t+10);

sort(v1.begin(), v1.end(), greater());

for_each(v1.begin(), v1.end(), Out(cout));cout<

return 0;

}