Free Practice Questions for Oracle 1z0-830 Exam

In Java, the ConcurrentHashMap class provides several constructors that allow for the customization of its initial capacity, load factor, and concurrency level. To configure a ConcurrentHashMap with an initial capacity of 42 and a concurrency level of 10, you can use the following constructor:

java

public ConcurrentHashMap(int initialCapacity, float loadFactor, int concurrencyLevel)

Parameters:

initialCapacity: The initial capacity of the hash table. This is the number of buckets that the hash table will have when it is created. In this case, it is set to 42.

loadFactor: A measure of how full the hash table is allowed to get before it is resized. The default value is 0.75, but in this case, it is set to 0.88.

concurrencyLevel: The estimated number of concurrently updating threads. This is used as a hint for internal sizing. In this case, it is set to 10.

Therefore, to create a ConcurrentHashMap with an initial capacity of 42, a load factor of 0.88, and a concurrency level of 10, you can use the following code:

java

var concurrentHashMap = new ConcurrentHashMap<>(42, 0.88f, 10);

Option Evaluations:

A. var concurrentHashMap = new ConcurrentHashMap(42);: This constructor sets the initial capacity to 42 but uses the default load factor (0.75) and concurrency level (16). It does not meet the requirement of setting the concurrency level to 10.

B. None of the suggestions.: This is incorrect because option E provides the correct configuration.

C. var concurrentHashMap = new ConcurrentHashMap();: This uses the default constructor, which sets the initial capacity to 16, the load factor to 0.75, and the concurrency level to 16. It does not meet the specified requirements.

D. var concurrentHashMap = new ConcurrentHashMap(42, 10);: This constructor sets the initial capacity to 42 and the load factor to 10, which is incorrect because the load factor should be a float value between 0 and 1.

E. var concurrentHashMap = new ConcurrentHashMap(42, 0.88f, 10);: This correctly sets the initial capacity to 42, the load factor to 0.88, and the concurrency level to 10, meeting all the specified requirements.

Therefore, the correct answer is option E.

java.io.Console is used for interactive input from the console.

Existing Methods in java.io.Console

reader() → Returns a Reader object.

readLine() → Reads a line of text from the console.

readLine(String fmt, Object... args) → Reads a formatted line.

readPassword() → Reads a password, returning a char[].

readPassword(String fmt, Object... args) → Reads a formatted password.

read() Does Not Exist

Consoledoes not have a read() method.

If character-by-character reading is required, use:

java

Console console = System.console();

Reader reader = console.reader();

int c = reader.read(); // Reads one character

read() is available inReader, butnot in Console.

Thus, the correct answer is:read() does not exist.

References:

Java SE 21 - Console API

Java SE 21 - Reader API

Pattern Matching in switch

The switch expression introduced inJava 21supportspattern matchingfor different types.

However,a switch expression must be exhaustive, meaningit must cover all possible cases or provide a default case.

Why does compilation fail?

input is an Object, and the switch expression attempts to pattern-match it to String, Double, and Integer.

If input had been of another type (e.g., Float or Long), there would beno matching case, leading to anon-exhaustive switch.

Javarequires a default caseto ensure all possible inputs are covered.

Corrected Code (Adding a default Case)

java

Object input = 42;

String result = switch (input) {

case String s -> "It's a string with value: " + s;

case Double d -> "It's a double with value: " + d;

case Integer i -> "It's an integer with value: " + i;

default -> "Unknown type";

};

System.out.println(result);

With this change, the codecompiles and runs successfully.

Output:

vbnet

It's an integer with value: 42

Thus, the correct answer is:Compilation failsdue to a missing default case.

References:

Java SE 21 - Pattern Matching for switch

Java SE 21 - switch Expressions

In this code, a TreeSet named frenchCities is created and populated with the following cities: "Paris", "Marseille", "Lyon", "Lille", and "Toulouse". The TreeSet class in Java stores elements in a sorted order according to their natural ordering, which, for strings, is lexicographical order.

Sorted Order of Elements:

When the elements are added to the TreeSet, they are stored in the following order:

"Lille"

"Lyon"

"Marseille"

"Paris"

"Toulouse"

headSet Method:

The headSet(E toElement) method of the TreeSet class returns a view of the portion of this set whose elements are strictly less than toElement. In this case, frenchCities.headSet("Marseille") will return a subset of frenchCities containing all elements that are lexicographically less than "Marseille".

Elements Less Than "Marseille":

From the sorted order, the elements that are less than "Marseille" are:

"Lille"

"Lyon"

Therefore, the output of the System.out.println statement will be [Lille, Lyon].

Option Evaluations:

A. [Paris]: Incorrect. "Paris" is lexicographically greater than "Marseille".

B. [Paris, Toulouse]: Incorrect. Both "Paris" and "Toulouse" are lexicographically greater than "Marseille".

C. [Lille, Lyon]: Correct. These are the elements less than "Marseille".

D. Compilation fails: Incorrect. The code compiles successfully.

E. [Lyon, Lille, Toulouse]: Incorrect. "Toulouse" is lexicographically greater than "Marseille".

In this code, the SmartPhone interface declares a method ring() with a boolean return type. The Iphone15 class implements the SmartPhone interface and provides an implementation for the ring() method.

However, in the Iphone15 class, the ring() method is declared without the public access modifier. In Java, when a class implements an interface, it must provide implementations for all the interface's methods with the same or a more accessible access level. Since interface methods are implicitly public, the implementing methods in the class must also be public. Failing to do so results in a compilation error.

Therefore, the Iphone15 class does not compile because the ring() method is not declared as public.

In this program, we have two classes, A and B, both implementing the Serializable interface, and a Test class with the main method.

Program Flow:

Serialization:

An instance of class A is created and assigned to the variable a.

An ObjectOutputStream is created to write to the file "o.ser".

The object a is serialized and written to the file.

The ObjectOutputStream is closed.

Deserialization:

An ObjectInputStream is created to read from the file "o.ser".

The program attempts to read an object from the file and cast it to an instance of class B.

The ObjectInputStream is closed.

Analysis:

Serialization Process:

The object a is an instance of class A and is serialized into the file "o.ser".

Deserialization Process:

When deserializing, the program reads the object from the file and attempts to cast it to class B.

However, the object in the file is of type A, not B.

Since A and B are distinct classes with no inheritance relationship, casting an A instance to B is invalid.

Exception Details:

Attempting to cast an object of type A to type B results in a ClassCastException.

The exception message would be similar to:

pgsql

Exception in thread "main" java.lang.ClassCastException: class A cannot be cast to class B

Conclusion:

The program compiles successfully but throws a ClassCastException at runtime when it attempts to cast the deserialized object to class B.

Why does the compilation fail?

TheJava switch statement does not support primitive type pattern matchingin switch expressions as of Java 21.

The case pattern case int i -> "integer"; isinvalidbecausepattern matching with primitive types (like int or long) is not yet supported in switch statements.

The error occurs at case int i -> "integer";, leading to acompilation failure.

Correcting the Code

Since myVar is of type Object,autoboxing converts 0 into an Integer.

To make the code compile, we should use Integer instead of int:

java

Object myVar = 0;

String print = switch (myVar) {

case Integer i -> "integer";

case Long l -> "long";

case String s -> "string";

default -> "";

};

System.out.println(print);

Output:

bash

integer

Thus, the correct answer is:Compilation fails.

References:

Java SE 21 - Pattern Matching for switch

Java SE 21 - switch Expressions

Understanding java.util.function.Predicate<T>

The Predicate interface represents a function thattakes an input and returns a boolean(true or false).

It is often used for filtering operations in functional programming and streams.

Analyzing the Methods:

and(Predicate<? super T> other)→Default method

Combines two predicates usinglogical AND(&&).

java

Predicate startsWithA = s -> s.startsWith("A");

Predicate hasLength3 = s -> s.length() == 3;

Predicate combined = startsWithA.and(hasLength3);

❌isEqual(Object targetRef)→Static method

Not a default method, because it doesnot operate on an instance.

java

Predicate isEqualToHello = Predicate.isEqual("Hello");

negate()→Default method

Negates a predicate (! operator).

java

Predicate notEmpty = s -> !s.isEmpty();

Predicate isEmpty = notEmpty.negate();

❌not(Predicate<? super T> target)→Static method (introduced in Java 11)

Not a default method, since it is static.

or(Predicate<? super T> other)→Default method

Combines two predicates usinglogical OR(||).

❌test(T t)→Abstract method

Not a default method, because every predicatemust implement this method.

Thus, the correct answers are:and(Predicate<? super T> other), negate(), or(Predicate<? super T> other)

References:

Java SE 21 - Predicate Interface

Java SE 21 - Functional Interfaces

In Java generics, wildcards are used to relax the type constraints of generic types. The extends wildcard () denotes an upper bounded wildcard, allowing any type that is a subclass of Type. Conversely, the super wildcard () denotes a lower bounded wildcard, allowing any type that is a superclass of Type.

Option A:

java

public List getListSuper() {

return new ArrayList();

}

Here, List represents a list that can hold IOException objects and objects of its supertypes. Since Exception is a superclass of IOException, ArrayList is compatible with List. Therefore, this method compiles successfully.

Option B:

java

public List getListExtends() {

return new ArrayList();

}

In this case, List represents a list that can hold objects of IOException and its subclasses. Since FileNotFoundException is a subclass of IOException, ArrayList is compatible with List. Thus, this method compiles successfully.

Option C:

java

public List getListExtends() {

return new ArrayList();

}

Here, List expects a list of IOException or its subclasses. However, Exception is a superclass of IOException, not a subclass. Therefore, ArrayList is not compatible with List, and this method will not compile.

Option D:

java

public List getListSuper() {

return new ArrayList();

}

In this scenario, List expects a list that can hold IOException objects and objects of its supertypes. Since FileNotFoundException is a subclass of IOException, ArrayList is not compatible with List, and this method will not compile.

Therefore, the methods in options A and B compile successfully, while those in options C and D do not.

Understanding Sealed Classes in Java

Asealed classrestricts which other classes can extend it.

A sealed classmust explicitly declare its permitted subclassesusing the permits keyword.

Subclasses can be declared as:

sealed(restricts further extension).

non-sealed(removes the restriction, allowing unrestricted subclassing).

final(prevents further subclassing).

Analyzing the Given Code

Vehicle is declared as sealed with permits Car, Bike, meaning only Car and Bike can extend it.

Car is declared as non-sealed, which means itis no longer sealedand can have subclasses.

Bike is declared as final, meaningit cannot be subclassed.

Using isSealed() Method

vehicleClass.isSealed() →truebecause Vehicle is explicitly marked as sealed.

carClass.isSealed() →falsebecause Car is marked non-sealed.

bikeClass.isSealed() →falsebecause Bike is final, and a final class isnot considered sealed.

Final Output

csharp

Is Vehicle sealed? true; Is Car sealed? false; Is Bike sealed? false

Thus, the correct answer is:"Is Vehicle sealed? true; Is Car sealed? false; Is Bike sealed? false"

References:

Java SE 21 - Sealed Classes

Java SE 21 - isSealed() Method