Free Practice Questions for Huawei H12-831_V1.0 Exam

Comprehensive and Detailed In-Depth Explanation:

Step 1: Identify the Primary Path

The shortest OSPF cost to 10.0.3.3/32 from R1 is through R5:

R1 → R5 (Cost 10) → R3 (Cost 10) = Total Cost 20

The primary outbound interface from R1 to R5 is GE0/0/1.

Step 2: Identify the Backup Path (OSPF IP FRR & ECMP)

OSPF IP Fast Reroute (FRR) provides a backup next-hop in case the primary link (R1 → R5) fails.

A feasible backup path must have a cost equal to or close to the primary path, but it must avoid the same failure point.

Alternative Path Calculation:

Path 1 (R1 → R2 → R3)

R1 → R2 (Cost 10), R2 → R3 (Cost 10) → Total Cost = 20 ✅

Uses interface GE0/0/2 on R1.

Path 2 (R1 → R4 → R3)

R1 → R4 (Cost 10), R4 → R3 (Cost 10) → Total Cost = 20 ✅

Uses interface GE0/0/3 on R1.

Final Decision on the Backup Interface

Since both paths R1 → R2 → R3 and R1 → R4 → R3 have equal costs, either can be used for backup.

However, R1 → R2 → R3 shares a direct cost path with R5, meaning it may not be preferred as a full FRR backup.

The best backup outbound interface in this scenario is GE0/0/3 (R1 → R4 → R3).

Final Answer: ✅ C (GE0/0/3)

References:

HCIP-Datacom-Advanced Routing & Switching Technology V1.0 – OSPF IP FRR (Fast Reroute) Mechanism

OSPF Equal-Cost Multi-Path (ECMP) and Backup Route Selection

OSPF Route Calculation and Best-Path Selection

Comprehensive and Detailed In-Depth Explanation:

Understanding the LSA Table in the Figure

The LSA Type displayed in the LSDB of R3 is an Intra-Area-Prefix-LSA (Type 9), with the following attributes:

LS Type: Intra-Area-Prefix-LSA (Type 9)

Link State ID: 0.0.0.1

Originating Router: 10.0.2.2 (R2)

Referenced LSA Type: 0x2001 (Router-LSA, Type 1)

Referenced Link State ID: 0.0.0.0

Referenced Originating Router: 10.0.2.2 (R2)

Prefix: 2000:2::/128

Analysis of the Statement

What is an Intra-Area-Prefix-LSA (Type 9)?

Used in OSPFv3 to advertise IPv6 prefixes associated with a Router-LSA (Type 1) or Network-LSA (Type 2).

Each router generates its own Router-LSA (Type 1) and references it in an Intra-Area-Prefix-LSA (Type 9).

How does this apply to R3's LSDB?

The LSA is generated by R2 (10.0.2.2), meaning R2 originated the prefix advertisement.

The referenced LSA is a Router-LSA, indicating that the IPv6 prefix is associated with R2's router advertisement.

Since R3 sees this LSA in its LSDB, it means R2 has advertised its IPv6 prefix (2000:2::/128) into the OSPFv3 domain.

✅ Since the LSA describes an IPv6 prefix associated with R2’s Router-LSA, the statement is TRUE.

Final Conclusion:

✅ The LSA is generated by R2 and describes the IPv6 prefix associated with the Router-LSA.✅ Thus, the correct answer is: A. TRUE.

Comprehensive and Detailed In-Depth Explanation:

Understanding the BGP Network Topology in the Question:

BGP Peering & Route Distribution

Each router forms EBGP peer relationships with directly connected neighbors.

R1 and R4 import the static route 192.168.1.0/24 into BGP and advertise it to their peers.

Community attributes are attached to routes to influence routing policies.

Effect of Community Attribute 1:1

R1 marks 192.168.1.0/24 with community 1:1 before advertising it.

R3 has a policy that rejects any routes with community attribute 1:1.

Since R1’s advertisement contains 1:1, R3 will not accept 192.168.1.0/24 from R2.

Route Selection and Traffic Flow Analysis:

R1 advertises 192.168.1.0/24 with community 1:1 to R2.

R3 rejects this route from R2 because of the configured routing policy.

R4 also advertises 192.168.1.0/24 to its EBGP neighbors without community 1:1.

R5 learns the route from R4 and advertises it to R3.

Since R5’s advertisement does not include community 1:1, R3 accepts the route from R5.

Thus, the best available path for R3 to reach 192.168.1.0/24 is R3 → R5 → R1.

✅ Correct Path: R3 → R5 → R1

Checking Each Option:

❌ Option A: R3 → R2 → R4 (Incorrect)

R3 does not learn the route from R2 because it rejects community 1:1.

Since R1 added 1:1, and R2 propagated the same community, R3 will not accept this path.

❌ Option B: R3 does not have a route to 192.168.1.0/24 (Incorrect)

R3 does have a route, but it learns it from R5 instead of R2.

❌ Option C: R3 → R2 → R1 (Incorrect)

R1 marked the route with 1:1, and R2 advertised it with the same community.

Since R3 rejects 1:1 routes, it will not use this path.

✅ Option D: R3 → R5 → R1 (Correct)

R5 learns the route from R4, which does not have community 1:1, and advertises it to R3.

R3 accepts this route and forwards traffic to R5, which sends it to R1.

Final Conclusion:

✅ D. The correct path for traffic from R3 to 192.168.1.0/24 is R3 → R5 → R1.

Thus, the correct answer is: D.

Comprehensive and Detailed In-Depth Explanation:To determine whether the statement is true or false, we need to analyze the OSPF network, the cost values of the links, the primary and backup paths, and the role of OSPF IP Fast Reroute (FRR) enabled on R1. Let’s break it down step by step:

Understanding the Network Topology and Costs:

The network consists of four routers: R1, R2, R3, and R4.

The destination network is 10.0.3.3/32, located at R3.

The link costs are as follows:

R1 to R2: Cost = 10

R1 to R4: Cost = 10

R4 to R2: Cost = 20

R2 to R3: Cost = 5

The total cost of a path is the sum of the costs of all links in that path.

Calculating the Primary Path Cost (R1 -> R2 -> R3):

Path: R1 -> R2 (cost = 10) -> R3 (cost = 5)

Total cost = 10 + 5 = 15

This is the shortest path (lowest cost) from R1 to R3, as stated in the question. OSPF uses the Dijkstra algorithm to calculate the shortest path based on link costs, so R1 will naturally select R1 -> R2 -> R3 as the primary path to reach 10.0.3.3/32.

Calculating the Backup Path Cost (R1 -> R4 -> R2 -> R3):

Path: R1 -> R4 (cost = 10) -> R2 (cost = 20) -> R3 (cost = 5)

Total cost = 10 + 20 + 5 = 35

This path has a higher cost (35) compared to the primary path (15), which is expected for a backup path. The backup path is not used under normal conditions but is precomputed for fast failover in case the primary path fails.

Role of OSPF IP Fast Reroute (FRR):

OSPF IP FRR is a mechanism designed to provide fast convergence in case of link or node failures by precomputing backup paths. When enabled on R1, FRR ensures that R1 has a precomputed backup path to quickly switch traffic to an alternate route (e.g., R1 -> R4 -> R2 -> R3) if the primary path (R1 -> R2 -> R3) fails.

FRR typically uses Loop-Free Alternates (LFA) or other techniques to ensure the backup path does not create loops and is immediately available. In this case, the backup path R1 -> R4 -> R2 -> R3 is valid because:

It does not loop back to R1.

It reaches R3, the destination.

The cost (35) is higher than the primary path (15), but this is acceptable for a backup path.

The question states that OSPF IP FRR is enabled on R1, and the backup path is explicitly given as R1 -> R4 -> R2 -> R3. This aligns with FRR’s purpose of maintaining a precomputed backup path.

Verifying the Statement:

The statement claims: “The primary path from R1 to 10.0.3.3/32 is R1 -> R2 -> R3, and the backup path is R1 -> R4 -> R2 -> R3.”

We calculated that the primary path (R1 -> R2 -> R3) has a cost of 15, which is the shortest path and correct for OSPF’s behavior.

The backup path (R1 -> R4 -> R2 -> R3) has a cost of 35, which is higher but valid as a backup path, especially with OSPF IP FRR enabled on R1 to ensure fast failover.

Both paths are correctly identified in the question, and OSPF IP FRR’s presence on R1 supports the existence of a precomputed backup path. Therefore, the statement is accurate.

Conclusion:

The primary path (R1 -> R2 -> R3) and backup path (R1 -> R4 -> R2 -> R3) are correctly described, and OSPF IP FRR on R1 ensures the backup path is precomputed and ready for use. Thus, the statement is true.

References (Based on HCIP-Datacom-Advanced Routing & Switching Technology Concepts):

OSPF Path Calculation: HCIP-Datacom documentation on OSPF’s Dijkstra algorithm and cost-based path selection (e.g., Section on OSPF Routing Metrics).

OSPF IP Fast Reroute (FRR): HCIP-Datacom coverage of FRR mechanisms, including Loop-Free Alternates and backup path computation (e.g., Chapter on OSPF Advanced Features and High Availability).

Link Cost and Path Optimization: HCIP-Datacom explanation of link cost configuration and OSPF path selection (e.g., Section on OSPF Network Design and Optimization).

Based on the provided image and the context of the HCIP-Datacom-Advanced Routing & Switching Technology exam, I’ll format and answer the question you’ve shared. I’ll ensure the response is accurate, detailed, and aligned with the official HCIP-Datacom documentation, while correcting any typos and providing a comprehensive explanation. Since you’ve only provided one question in the image, I’ll address it in the requested format. If there are additional questions, please share them, and I’ll format and answer them similarly.

Comprehensive and Detailed In-Depth Explanation:

To determine which statements are false, we need to understand how OSPFv3 and IS-IS work together, and how Inter-Area-Router LSAs (Type 3 LSAs) are generated in OSPF:

1. Understanding OSPF Inter-Area LSAs (Type 3)

OSPF generates Type 3 LSAs (Inter-Area-Prefix LSAs) to advertise networks between areas.

Only Area Border Routers (ABRs) generate Inter-Area LSAs.

Type 3 LSAs allow routes to be advertised from one OSPF area to another (e.g., from Area 0 to Area 1 or Area 2).

2. Analysis of Each Answer Option:

✅ A. "R3 generates an Inter-Area-Router-LSA in Area 0." → TRUE

R3 is an ABR (connecting IS-IS and OSPF Area 0).

Since R3 is importing IS-IS routes into OSPFv3, it must generate Type 3 LSAs to advertise those routes in Area 0.

This statement is correct.

✅ B. "R2 generates an Inter-Area-Router-LSA in Area 0." → TRUE

R2 is also an ABR (connecting IS-IS and OSPF Area 0).

Like R3, R2 imports IS-IS routes into OSPFv3 and advertises them into Area 0 using Type 3 LSAs.

This statement is correct.

❌ C. "R1 generates an Inter-Area-Router-LSA in Area 2." → FALSE

R1 is not an ABR.

Only ABRs generate Type 3 LSAs, and R1 is not an ABR between Area 2 and Area 0.

This statement is false.

❌ D. "R2 generates an Inter-Area-Router-LSA in Area 1." → FALSE

Area 1 is a stub area, and stub areas do not allow Inter-Area-Router LSAs (Type 3 LSAs) for external routes.

R2 does not generate Inter-Area LSAs in Area 1 because OSPF prevents this in stub areas.

This statement is false.

Comprehensive and Detailed In-Depth Explanation:

Understanding the IS-IS Network Structure in the Question:

Router Roles & IS-IS Levels:

R1 and R3: Level-1 routers.

R2: Level-1-2 router (interconnects Level-1 and Level-2 areas).

R4: Level-2 router.

Key Command Used: default-route-advertise always level-1

This command forces R1 to advertise a default route (0.0.0.0/0) to all Level-1 routers.

In an IS-IS network:

Level-1 routers do not see Level-2 routes unless a default route is provided.

The default route is propagated only within the Level-1 area and does not affect Level-2 routers unless explicitly redistributed.

Route Distribution Analysis:

R1 (Level-1) imports the default route and advertises it to all Level-1 routers.✅ R1 has the default route.

R3 (Level-1) is in the same Level-1 area as R1, so it receives the default route from R1.✅ R3 has the default route.

R2 (Level-1-2) connects Level-1 and Level-2. Since it participates in Level-1, it also learns the default route from R1.✅ R2 has the default route.

R4 (Level-2) is not in Level-1 and does not receive the default route unless it is explicitly redistributed from Level-1 to Level-2, which is not stated in the question.❌ R4 does NOT have the default route.

Final Conclusion:

R1, R2, and R3 have the default route.

R4 does not have the default route.

Thus, the correct answer is:✅ R1, R2, and R3 have the default route in their routing tables.